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Proof step 2 from proof fill-sgn-03 (previous step)

# bits ≤ n + 1 ⊦ bits = [], fillsgn(n + 1, sgn(bits.rest)).rest = fillsgn(n, bits.rest)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
bits = boolvar + bits0, # bits ≤ n + 1 ⊦ bits = [], fillsgn(n + 1, sgn(bits0)).rest = fillsgn(n, bits0)

Rule argument

seq: bits ≠ [] ⊦ (boolvar ↔ bits.first) ∧ bits0 = bits.rest ↔ bits = boolvar + bits0 subst: [bits, boolvar, bits0] → [bits, boolvar, bits0] rotate: T spec: list-data inst: bitlista name: elim-list-c

Additional information

Used simplifier rules: bits ≠ [] ⊦ (boolvar ↔ bits.first) ∧ bits0 = bits.rest ↔ bits = boolvar + bits0; (elim) Used terms: bits, boolvar, bits0