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Proof step 5 from proof fill-sgn (previous step)

# sgn(bits) ≤ # bits ∧ sgn(bits) ≠ [] ⊦ mklist(sgn(bits).first, # bits - # sgn(bits)) + sgn(bits) = bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
# sgn(bits) ≤ # bits ⊦ bits = [], mklist(bits.first, # bits - # sgn(bits)) + sgn(bits) = bits

Rule argument

Additional information

Used simplifier rules: sgn-empty-01: ⊦ sgn(bits) = [] ↔ bits = [];%sgn-first-01: ⊦ bits ≠ [] → (sgn(bits).first ↔ bits.first);