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Proof step 1 from proof fill-size (conclusion)

⊦ fillsgn(# bits, bits) = bits

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ n ≤ # bits → fillsgn(n, bits) = bits

Rule argument

name: fillsgn-longer rotate: F subst: [bits, n] → [bits, # bits]

Additional information

Used simplifier rules: ⊦ ¬ m ≤ n ↔ n < m;% ⊦ ¬ n < n; Used terms: bits, # bits