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Proof step 3 from proof fix-zero (previous step)

¬ ¬ 0 < # bits ⊦ fix(0, bits) = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ fix(0, bits) = [], bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ # bits = 0 ↔ bits = [];% ⊦ 0 < n ↔ n ≠ 0;