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Proof step 1 from proof inv-empty (conclusion)

⊦ bitsinvert(bits) = [] ↔ bits = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
bitsinvert(bits) = [] ⊦ bits = []

Rule argument

Additional information

Used simplifier rules: invert-base: ⊦ bitsinvert([]) = [];