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Proof step 11 from proof inv-fill (previous step)

bits = boolvar + bits0 ⊦ bits = [], mklist(¬ boolvar, n0) + bitsinvert(bits) = fillsgn(n0 + # bits, bitsinvert(bits)), n0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
⊦ n0 = 0, ((¬ boolvar)' + mklist(¬ boolvar, n0)) + bitsinvert(bits0) = fillsgn((1 + # bits0) + n0, (¬ boolvar)' + bitsinvert(bits0))

Rule argument

Additional information

Used simplifier rules: inv-append: ⊦ bitsinvert(bits + bits0) = bitsinvert(bits) + bitsinvert(bits0);%inv-one: ⊦ bitsinvert(boolvar ') = (¬ boolvar)';% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ mklist(boolvar, n) + boolvar ' = boolvar ' + mklist(boolvar, n);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits ≠ [];% ⊦ boolvar + bits = boolvar ' + bits;