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Proof step 2 from proof inv-fill (previous step)

⊦ bits = [], bitsinvert(fillsgn(n, bits)) = fillsgn(n, bitsinvert(bits))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ n ≤ # bits → fillsgn(n, bits) = bits
Proof step 4:
¬ n ≤ # bits ⊦ bits = [], bitsinvert(fillsgn(n, bits)) = fillsgn(n, bitsinvert(bits))
Proof step 14:
n ≤ # bits ⊦ bits = [], bitsinvert(bits) = fillsgn(n, bitsinvert(bits))

Rule argument

name: fillsgn-longer rotate: F subst: [bits, n] → [bits, n]

Additional information

Used terms: bits, n