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Proof step 9 from proof inv-fill (previous step)

n = n0 + # bits ∧ # bits ≤ n, # bits < n ⊦ bits = [], mklist(¬ bits.first, n0) + bitsinvert(bits) = fillsgn(n, bitsinvert(bits))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
⊦ bits = [], mklist(¬ bits.first, n0) + bitsinvert(bits) = fillsgn(n0 + # bits, bitsinvert(bits)), n0 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m < m + n ↔ n ≠ 0;% ⊦ m < n → m ≤ n;