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Proof step 1 from proof inv-first-01 (conclusion)

⊦ bitsinvert(bits) = true ' + bits0 ↔ bits = false ' + bitsinvert(bits0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
bitsinvert(bits) = true ' + bits0, false ∈ bits ⊦ bits = false ' + bitsinvert(bits0)

Rule argument

Additional information

Used simplifier rules: invert-zero: ⊦ bitsinvert(false ' + bits) = true + bitsinvert(bits);%inv-inv: ⊦ bitsinvert(bitsinvert(bits)) = bits;%inv-in-02: ⊦ true ∈ bitsinvert(bits) ↔ false ∈ bits;% ⊦ boolvar ' + bits = bits0 → boolvar ∈ bits0; (forward)% ⊦ bits + bits0 = bits + bits1 ↔ bits0 = bits1;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar + bits = boolvar ' + bits;