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Proof step 1 from proof inv-first (conclusion)

⊦ bitsinvert(bits) = false ' + bits0 ↔ bits = true ' + bitsinvert(bits0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
bitsinvert(bits) = false ' + bits0, true ∈ bits ⊦ bits = true ' + bitsinvert(bits0)

Rule argument

Additional information

Used simplifier rules: invert-one: ⊦ bitsinvert(true ' + bits) = false + bitsinvert(bits);%inv-inv: ⊦ bitsinvert(bitsinvert(bits)) = bits;%inv-in-01: ⊦ false ∈ bitsinvert(bits) ↔ true ∈ bits;% ⊦ boolvar ' + bits = bits0 → boolvar ∈ bits0; (forward)% ⊦ bits + bits0 = bits + bits1 ↔ bits0 = bits1;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar + bits = boolvar ' + bits;