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Proof step 1 from proof inv-intro (conclusion)
⊦ bits = bits0 ↔ bitsinvert(bits) = bitsinvert(bits0)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
bitsinvert(bits) = bitsinvert(bits0) ⊦ bits = bits0
Rule argument
Additional information