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Proof step 9 from proof inv-sgn (previous step)

bits0 ≠ [] ∧ (bits0.first ↔ boolvar), bitsinvert(sgn(bits0)) = sgn(bitsinvert(bits0)) ⊦ bitsinvert(sgn(bits0)) = sgn((¬ boolvar)' + bitsinvert(bits0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
bitsinvert(sgn(bits0)) = sgn(bitsinvert(bits0)) ⊦ sgn(bitsinvert(bits0)) = sgn((¬ bits0.first)' + bitsinvert(bits0)), bits0 = []

Proof step 9 from proof inv-sgn (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information