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Proof step 11 from proof lastn-fill-sgn (previous step)

# sgn(bits) < # bits, # sgn(bits) < n, n < # bits, # sgn(bits) + 1 < # bits ⊦ lastn(n, fillsgn(n, sgn(bits))) = lastn(n, bits), bits = [], n = # bits

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 12:
⊦ n = # bits → lastn(n, bits) = bits
Proof step 13:
n ≠ # fillsgn(n, sgn(bits)), # sgn(bits) < # bits, # sgn(bits) < n, n < # bits, # sgn(bits) + 1 < # bits ⊦ lastn(n, fillsgn(n, sgn(bits))) = lastn(n, bits), bits = [], n = # bits
Proof step 16:
n = # fillsgn(n, sgn(bits)), # sgn(bits) < # bits, # sgn(bits) < n, n < # bits, # sgn(bits) + 1 < # bits ⊦ fillsgn(n, sgn(bits)) = lastn(n, bits), bits = [], n = # bits

Rule argument

seq: ⊦ n = # bits → lastn(n, bits) = bits subst: [bits, n] → [fillsgn(n, sgn(bits)), n] rotate: F spec: list-del inst: bitlista name: lastN-all

Additional information

Used terms: fillsgn(n, sgn(bits)), n