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Proof step 14 from proof lastn-fill-sgn (previous step)

# sgn(bits) + 1 < # bits, n < # bits, # sgn(bits) < n, # sgn(bits) < # bits ⊦ n = # fillsgn(n, sgn(bits)), n = # bits, bits = [], lastn(n, fillsgn(n, sgn(bits))) = lastn(n, bits)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 15:
⊦ # bits ≤ n → # fillsgn(n, bits) = n

Rule argument

name: fill-length rotate: F subst: [bits, n] → [sgn(bits), n]

Additional information

Used simplifier rules: ⊦ ¬ m ≤ n ↔ n < m;% ⊦ m < n → ¬ n < m; Used terms: sgn(bits), n