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Proof step 2 from proof lastn-fill-sgn (previous step)

⊦ bits = [], lastn(n, fillsgn(n, sgn(bits))) = lastn(n, fillsgn(n, bits))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ # bits ≤ n → fillsgn(n, sgn(bits)) = fillsgn(n, bits)
Proof step 4:
¬ # bits ≤ n ⊦ bits = [], lastn(n, fillsgn(n, sgn(bits))) = lastn(n, fillsgn(n, bits))

Rule argument

name: fill-sgn-01 rotate: F subst: [bits, n] → [bits, n]

Additional information

Used terms: bits, n