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Proof step 37 from proof lastn-fill-sgn (previous step)

¬ true ∈ bits1 ∧ bits1 ≠ [], # bits0 = # fillsgn(# bits0, sgn(false ' + bits0)), # sgn(false ' + bits0) < # bits1 + # bits0, # sgn(false ' + bits0) < # bits0, # sgn(false ' + bits0) + 1 < # bits1 + # bits0 ⊦ bits0 = [], fillsgn(# bits0, sgn(false ' + bits0)) = bits0, bits1 + bits0 = [], bits1 = [], true ∈ bits1 ∧ false ∈ bits1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 38:
# bits0 = # fillsgn(# bits0, sgn(false ' + bits0)), # sgn(false ' + bits0) + 1 < # bits1 + # bits0, # sgn(false ' + bits0) < # bits0, # sgn(false ' + bits0) < # bits1 + # bits0 ⊦ bits1 = [], bits1 + bits0 = [], fillsgn(# bits0, sgn(false ' + bits0)) = bits0, bits0 = [], true ∈ bits1

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ m < n ∧ n = n0 → m < n0; (forward)