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Proof step 20 from proof sgn-append-03 (previous step)

⊦ sgn(boolvar1 ' + bits) = sgn((¬ boolvar0)' + boolvar1 ' + bits), boolvar0 ↔ boolvar1

User applied rule case distinction

And closed the goal!

Rule argument

pos: right 2

Additional information

Used simplifier rules: sgn-rec: ⊦ sgn(boolvar ' + boolvar ' + bits) = sgn(boolvar ' + bits);%sgn-rec: ⊦ sgn(boolvar ' + boolvar ' + bits) = sgn(boolvar ' + bits);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;