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Proof step 8 from proof sgn-append-06 (previous step)

(¬ boolvar) ∈ bits ⊦ sgn(bits + boolvar ' + bits1) = sgn(bits) + boolvar ' + bits1, (boolvar ∨ true ∈ bits) ∧ (¬ boolvar ∨ false ∈ bits)

User applied rule case distinction

And closed the goal!

Rule argument

pos: right 2

Additional information

Used simplifier rules: sgn-zeros: ⊦ ¬ true ∈ bits → sgn(bits + false ' + bits0) = sgn(false ' + bits0);% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;