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Proof step 25 from proof sgn-ex-01 (previous step)

true ∈ bits0 ⊦ mklist(¬ false, # bits0) ≠ bits0, ∃ boolvar2, n0, boolvar3, bits1. false ' + bits0 = mklist(boolvar2, n0) + boolvar3 ' + bits1 ∧ sgn(mklist(boolvar2, n0) + boolvar3 ' + bits1) = boolvar2 ' + boolvar3 ' + bits1 ∧ ¬(boolvar2 ↔ boolvar3) ∧ n0 ≠ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 26:
mklist(true, # bits0) = bits0, true ∈ bits0 ⊦ ∃ boolvar2, n0, boolvar3, bits1. false ' + bits0 = mklist(boolvar2, n0) + boolvar3 ' + bits1 ∧ sgn(mklist(boolvar2, n0) + boolvar3 ' + bits1) = boolvar2 ' + boolvar3 ' + bits1 ∧ ¬(boolvar2 ↔ boolvar3) ∧ n0 ≠ 0

Proof step 25 from proof sgn-ex-01 (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information