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Proof step 33 from proof sgn-ex-01 (previous step)

mklist(false, # bits0) = bits0, false ∈ bits0 ⊦ ∃ boolvar2, n0, boolvar3, bits1. true ' + bits0 = mklist(boolvar2, n0) + boolvar3 ' + bits1 ∧ sgn(mklist(boolvar2, n0) + boolvar3 ' + bits1) = boolvar2 ' + boolvar3 ' + bits1 ∧ ¬(boolvar2 ↔ boolvar3) ∧ n0 ≠ 0

User applied rule exists right

And obtained the following new goals

Proof step 34:
mklist(false, # bits0) = bits0, false ∈ bits0 ⊦ true ' + bits0 = mklist(true, 1) + false ' + bits0.rest ∧ sgn(mklist(true, 1) + false ' + bits0.rest) = true ' + false ' + bits0.rest ∧ ¬(true ↔ false) ∧ 1 ≠ 0, ∃ boolvar2, n0, boolvar3, bits1. true ' + bits0 = mklist(boolvar2, n0) + boolvar3 ' + bits1 ∧ sgn(mklist(boolvar2, n0) + boolvar3 ' + bits1) = boolvar2 ' + boolvar3 ' + bits1 ∧ ¬(boolvar2 ↔ boolvar3) ∧ n0 ≠ 0

Rule argument

pos: right 1 terms: true, 1, false, bits0.rest abort: F discard: F computed: F

Additional information

Used terms: true, 1, false, bits0.rest