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Proof step 5 from proof sgn-fill (previous step)

n < # bits ⊦ sgn(fillsgn(n, bits)) = sgn(bits), bits = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ n ≤ # bits → fillsgn(n, bits) = bits

Rule argument

name: fillsgn-longer rotate: F subst: [bits, n] → [bits, n]

Additional information

Used simplifier rules: ⊦ ¬ m ≤ n ↔ n < m;% ⊦ m < n → ¬ n < m; Used terms: bits, n