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Proof step 2 from proof sgn-first (previous step)

∀ boolvar. sgn(boolvar ' + bits0).first ↔ boolvar ⊦ sgn(boolvar0 ' + (boolvar + bits0)).first ↔ boolvar0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
∀ boolvar. sgn(boolvar ' + bits0).first ↔ boolvar ⊦ sgn(boolvar0 ' + boolvar ' + bits0).first ↔ boolvar0

Rule argument

Additional information

Used simplifier rules: ⊦ boolvar + bits = boolvar ' + bits;