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Proof step 3 from proof sgn-in (previous step)

∀ boolvar. sgn(boolvar ' + bits0) = boolvar ' ∨ (¬ boolvar) ∈ bits0 ⊦ sgn(boolvar0 ' + (boolvar + bits0)) = boolvar0 ' ∨ (¬ boolvar0) ∈ boolvar + bits0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;%⊦ ¬ boolvar ∈ boolvar0 ' + bits ↔ ¬(boolvar ↔ boolvar0) ∧ ¬ boolvar ∈ bits;% ⊦ boolvar + bits = boolvar ' + bits;