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Proof step 2 from proof sgn-last-01 (previous step)

⊦ sgn((¬ boolvar0)' + bits + boolvar0 ') = sgn((¬ boolvar0)' + bits) + boolvar0 '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
(¬ boolvar) ∈ bits ⊦ sgn(boolvar ' + bits + boolvar0 ') = sgn(boolvar ' + bits) + boolvar0 '
Proof step 4:
¬ (¬ ¬ boolvar0) ∈ bits ⊦ sgn((¬ boolvar0)' + bits + boolvar0 ') = sgn((¬ boolvar0)' + bits) + boolvar0 '

Rule argument

name: sgn-last rotate: F subst: [boolvar0, bits, boolvar] → [boolvar0, bits, ¬ boolvar0]

Additional information

Used terms: boolvar0, bits, ¬ boolvar0