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Proof step 3 from proof sgn-last-03 (previous step)

bits = boolvar + bits0, (¬ boolvar) ∈ bits0 ⊦ bits = [], sgn(bits + boolvar0 ') = sgn(bits) + boolvar0 '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
(¬ boolvar) ∈ bits0 ⊦ sgn((boolvar ' + bits0) + boolvar0 ') = sgn(boolvar ' + bits0) + boolvar0 '

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits ≠ [];% ⊦ boolvar + bits = boolvar ' + bits;