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Proof step 32 from proof sgn-last-04 (previous step)

∀ boolvar. ¬ boolvar ∨ false ∈ bits1 → sgn((true ' + bits1) + boolvar ') = sgn(true ' + bits1) + boolvar ' ⊦ sgn(true ' + bits1 + false ') = sgn(true ' + bits1) + false '

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: false

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1; Used terms: false