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Proof step 1 from proof sgn-last-diff (conclusion)

(¬ boolvar) ∈ bits ⊦ sgn(bits + boolvar ') = sgn(bits) + boolvar '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
(¬ bits.first) ∈ bits.rest, bits ≠ [] ⊦ sgn(bits + boolvar0 ') = sgn(bits) + boolvar0 '
Proof step 3:
¬((¬ bits.first) ∈ bits.rest ∧ bits ≠ []), (¬ boolvar) ∈ bits ⊦ sgn(bits + boolvar ') = sgn(bits) + boolvar '

Rule argument

name: sgn-last-03 rotate: F subst: [boolvar0, bits] → [boolvar, bits]

Additional information

Used terms: boolvar, bits