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Proof step 11 from proof sgn-last-diff (previous step)

(¬ boolvar) ∈ bits0 ⊦ sgn(boolvar0 ' + boolvar ') = boolvar0 ' + boolvar ', (¬ boolvar0) ∈ bits0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 12:
⊦ bits ≠ [] ∧ (bits.first ↔ ¬ boolvar) → sgn(boolvar ' + bits) = boolvar ' + bits
Proof step 13:
¬(boolvar ' ≠ [] ∧ (boolvar '.first ↔ ¬ boolvar0)), (¬ boolvar) ∈ bits0 ⊦ sgn(boolvar0 ' + boolvar ') = boolvar0 ' + boolvar ', (¬ boolvar0) ∈ bits0

Rule argument

name: sgn-base-03 rotate: F subst: [bits, boolvar] → [boolvar ', boolvar0]

Additional information

Used terms: boolvar ', boolvar0