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Proof step 5 from proof sgn-last-same (previous step)

⊦ sgn(bits + boolvar ') = boolvar ', (¬ boolvar) ∈ bits, boolvar ∧ ¬ false ∈ bits

User applied rule case distinction

And obtained the following new goals

Proof step 6:
⊦ boolvar, sgn(bits + boolvar ') = boolvar ', (¬ boolvar) ∈ bits
Proof step 9:
⊦ ¬ false ∈ bits, sgn(bits + boolvar ') = boolvar ', (¬ boolvar) ∈ bits

Rule argument

pos: right 3

Additional information