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Proof step 2 from proof sgn-lastn-01 (previous step)

n ≤ # sgn(bits) ⊦ bits = [], lastn(n, sgn(bits)) = lastn(n, bits)

User applied rule structural induction

And obtained the following new goals

Proof step 3:
∀ n. n ≤ # sgn(bits0) → bits0 = [] ∨ lastn(n, sgn(bits0)) = lastn(n, bits0), n ≤ # sgn(boolvar + bits0) ⊦ boolvar + bits0 = [], lastn(n, sgn(boolvar + bits0)) = lastn(n, boolvar + bits0)

Rule argument

indvar: bits

Additional information

Used simplifier rules: bitlist freely generated by [], +;;