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Proof step 15 from proof sgn-length-02 (previous step)

bits0 = boolvar0 + bits, # sgn(bits0) < 2 + # bits0, 3 + # bits0 ≤ # sgn(boolvar ' + bits0) ⊦ bits0 = [], boolvar0 ↔ boolvar

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
4 + # bits ≤ # sgn(boolvar ' + boolvar0 ' + bits), # sgn(boolvar0 ' + bits) < 3 + # bits ⊦ boolvar0 ↔ boolvar

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;%n < n0 ⊦ (* n) ≠ m0 + (* n0);% ⊦ m < n → n ≠ 0; (forward)% ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits ≠ [];% ⊦ boolvar + bits = boolvar ' + bits;