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Proof step 6 from proof sgn-length-02 (previous step)

bits = boolvar0 + bits0, 2 + # bits ≤ # sgn(boolvar ' + bits) ⊦ boolvar0 ↔ boolvar, bits = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
3 + # bits0 ≤ # sgn(boolvar ' + boolvar0 ' + bits0) ⊦ boolvar0 ↔ boolvar

Rule argument

Additional information

Used simplifier rules: ⊦ # boolvar ' = 0 +1;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar ' + bits ≠ [];% ⊦ boolvar + bits = boolvar ' + bits;