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Proof step 8 from proof sgn-length-02 (
previous step
)
bits ≠ [] ∧ (bits.first ↔ boolvar), 2 + # bits ≤ # sgn(bits) ⊦
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 9
:
2 + # bits ≤ # sgn(bits) ⊦ bits = []
Rule argument
Additional information