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Proof step 4 from proof sgn-not-empty (previous step)

sgn(boolvar ' + bits0) = [] ⊦ bits0 = [], sgn(bits0) = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
bits ≠ [], bits.first ↔ boolvar ⊦ sgn(boolvar ' + bits) = sgn(bits)
Proof step 6:
¬(bits0 ≠ [] ∧ (bits0.first ↔ boolvar)), sgn(boolvar ' + bits0) = [] ⊦ bits0 = [], sgn(bits0) = []

Rule argument

name: sgn-rec-01 rotate: F subst: [bits, boolvar] → [bits0, boolvar]

Additional information

Used terms: bits0, boolvar