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Proof step 11 from proof sgn-notsame-01 (previous step)

sgn(bits0) = boolvar0 ' + boolvar0 ' + bits1, boolvar0 ∈ bits0, ∀ boolvar, bits1. sgn(bits0) ≠ boolvar ' + boolvar ' + bits1 ⊦ bits0 = []

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 3 terms: boolvar0, bits1

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1; Used terms: boolvar0, bits1