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Proof step 10 from proof sgn-one-01 (previous step)

sgn(boolvar ' + bits0) = true ', sgn(bits0) = true ' ∧ false ∈ bits0 → bits0 = [] ⊦ bits0.first ↔ boolvar, ¬ false ∈ bits0 ∧ boolvar

User applied rule case distinction

And obtained the following new goals

Proof step 11:
bits0.first, sgn(boolvar ' + bits0) = true ', sgn(bits0) = true ' ∧ false ∈ bits0 → bits0 = [] ⊦ boolvar, ¬ false ∈ bits0 ∧ boolvar
Proof step 13:
boolvar, sgn(boolvar ' + bits0) = true ', sgn(bits0) = true ' ∧ false ∈ bits0 → bits0 = [] ⊦ bits0.first, ¬ false ∈ bits0 ∧ boolvar

Rule argument

pos: right 1

Additional information