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Proof step 12 from proof sgn-sgn-01 (previous step)

∀ bits0. sgn(sgn(boolvar ' + bits) + bits0) = sgn((boolvar ' + bits) + bits0) ⊦ sgn(sgn(boolvar ' + bits) + bits1) = sgn(boolvar ' + bits + bits1)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: bits1

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1; Used terms: bits1