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Proof step 2 from proof sgn-sgn-01 (previous step)

∀ bits1. sgn(sgn(bits0) + bits1) = sgn(bits0 + bits1) ⊦ sgn(sgn(boolvar + bits0) + bits1) = sgn((boolvar + bits0) + bits1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ boolvar + bits = boolvar ' + bits;