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Proof step 6 from proof sgn-zero (
previous step
)
¬(bits0 ≠ [] ∧ (bits0.first ↔ false)), sgn(bits0) = false ' ⊦ sgn(false ' + bits0) = false ', bits0 = [], true ∈ bits0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 7
:
sgn(bits0) = false ', bits0.first ⊦ sgn(false ' + bits0) = false ', bits0 = [], true ∈ bits0
Rule argument
Additional information