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Proof step 5 from proof succ-ex (previous step)

⊦ false ∈ bits0, ∃ bits, bits2. bits1 + false ' + bits0 = bits + false ' + bits2 ∧ ¬ false ∈ bits2 ∧ bits1 + true ' + bitsinvert(bits0) = bits + true ' + bitsinvert(bits2)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: bits1, bits0

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1; Used terms: bits1, bits0