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Proof step 5 from proof succ-exinv (previous step)

⊦ true ∈ bits0, ∃ bits, bits2. ¬ true ∈ bits2 ∧ bits1 + true ' + bits0 = bits + true ' + bits2 ∧ bitsinvert(bits1) + true ' + bits0 = bitsinvert(bits) + true ' + bits2

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: bits1, bits0

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1; Used terms: bits1, bits0