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Proof step 10 from proof succ-fill (previous step)

# bits0 < n, 1 + # bits0 < n, false ∈ bits0 ⊦ mklist(boolvar, n - # bits0) + bits0 +1 = fillsgn(n, boolvar ' + bits0 +1)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 11:
n = n0 + # bits0 ∧ # bits0 ≤ n, # bits0 < n, 1 + # bits0 < n, false ∈ bits0 ⊦ mklist(boolvar, n0) + bits0 +1 = fillsgn(n, boolvar ' + bits0 +1)

Rule argument

seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [n, # bits0, n0] rotate: T spec: nat inst: name: elim-sub

Additional information

Used simplifier rules: ⊦ ¬ m ≤ n ↔ n < m;% ⊦ m < n → ¬ n < m;%n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: n, # bits0, n0