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Proof step 15 from proof succ-fill (previous step)

false ∈ bits0, n ≤ 1 + # bits0 ⊦ boolvar ' + bits0 +1 = fillsgn(n, boolvar ' + bits0 +1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 16:
⊦ n ≤ # bits → fillsgn(n, bits) = bits

Rule argument

name: fillsgn-longer rotate: F subst: [bits, n] → [boolvar ' + bits0 +1, n]

Additional information

Used simplifier rules: succ-len: ⊦ false ∈ bits → # bits +1 = # bits;% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ # boolvar ' = 0 +1;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ ¬ m ≤ n ↔ n < m;% ⊦ m + n = n + m;% ⊦ m ≤ n → (n < m ↔ false); Used terms: boolvar ' + bits0 +1, n