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Proof step 5 from proof succ-first-01 (previous step)

bits = boolvar + bits0, true ∈ bits +1.rest ⊦ bits +1.first ↔ boolvar, bits = [], false ∈ bits0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
true ∈ (boolvar ' +1 + bitsinvert(bits0)).rest ⊦ (boolvar ' +1 + bitsinvert(bits0)).first ↔ boolvar, false ∈ bits0

Rule argument

Additional information

Used simplifier rules: succ-zeros-01: ⊦ ¬ false ∈ bits0 → (bits + bits0)+1 = bits +1 + bitsinvert(bits0);% ⊦ boolvar ' + bits ≠ [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ boolvar + bits = boolvar ' + bits;