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Proof step 1 from proof succ-rec-02 (conclusion)

⊦ 0 ≠ # bits ∧ bits.last → bits +1 = bits.butlast +1 + false '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
bits.last ⊦ bits +1 = bits.butlast +1 + false ', bits = []

Rule argument

Additional information

Used simplifier rules: ⊦ # bits = 0 ↔ bits = [];