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Proof step 2 from proof bcompl-bib (previous step)

~128 ≤ i, i ≤ 127 ⊦ b2i(i2b(bcompl(i))) = bcompl(i)

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ bcompl(b2i(by)) = b2i(i2b(bcompl(b2i(by))))

Rule argument

name: fits-law-compl subst: [by] → [i2b(i)]

Additional information

Used simplifier rules: bib-in-01: ⊦ ~128 ≤ i ∧ i ≤ 127 → b2i(i2b(i)) = i; Used terms: i2b(i)