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Proof step 2 from proof bib-lower (previous step)

~256 < i, i < ~128, i < 0 ⊦ b2i(i2b(i)) = i + 256

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i < 0 ∧ i % 256 < ~128 → b2i(i2b(i)) = i % 256 + 256
Proof step 4:
¬(i < 0 ∧ i % 256 < ~128), ~256 < i, i < ~128, i < 0 ⊦ b2i(i2b(i)) = i + 256
Proof step 7:
i < 0 ∧ i % 256 < ~128, ~256 < i, i < ~128, i < 0 ⊦ i % 256 + 256 = i + 256

Rule argument

name: bib-neg-low rotate: F subst: [i] → [i]

Additional information

Used terms: i