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Proof step 10 from proof bib-ls-same-01 (
previous step
)
i ≤ ~256, i < 0, i % 256 + 256 < i, i % 256 < ~512 ⊦ i % 256 = 0
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 11
:
⊦ i0 - 1 ≤ ~ abs(j) ∧ j ≠ 0 → ¬ i % j < i0
Rule argument
seq: ⊦ i0 - 1 ≤ ~ abs(j) ∧ j ≠ 0 → ¬ i % j < i0 subst: [i0, j, i] → [~512, 256, i] rotate: F spec: int-div inst: name: mod-nls-04
Additional information
Used terms: ~512, 256, i