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Proof step 4 from proof bib-ls-same-01 (previous step)

b2i(i2b(i)) < i, i < 0 ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ i < 0 ∧ ~128 ≤ i % 256 → b2i(i2b(i)) = i % 256
Proof step 6:
¬(i < 0 ∧ ~128 ≤ i % 256), b2i(i2b(i)) < i, i < 0 ⊦
Proof step 12:
i < 0 ∧ ~128 ≤ i % 256, i % 256 < i, i < 0 ⊦

Rule argument

name: bib-neg-high rotate: F subst: [i] → [i]

Additional information

Used terms: i