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Proof step 12 from proof bib-ls-same (previous step)

i < b2i(i2b(i)), 0 ≤ i, 0 < b2i(i2b(i)) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 13:
⊦ 0 ≤ i ∧ 127 < i % 256 → b2i(i2b(i)) = i % 256 - 256
Proof step 14:
¬(0 ≤ i ∧ 127 < i % 256), i < b2i(i2b(i)), 0 ≤ i, 0 < b2i(i2b(i)) ⊦

Rule argument

name: bib-pos-high rotate: F subst: [i] → [i]

Additional information

Used simplifier rules: ⊦ i < j - i0 ↔ i + i0 < j;% ⊦ j ≤ i0 ∧ 0 < j → ¬ i0 < i % j; Used terms: i